Optimal. Leaf size=167 \[ -\frac{a^2 b \sqrt{a^2+2 a b x^2+b^2 x^4}}{3 x^9 \left (a+b x^2\right )}-\frac{3 a b^2 \sqrt{a^2+2 a b x^2+b^2 x^4}}{7 x^7 \left (a+b x^2\right )}-\frac{b^3 \sqrt{a^2+2 a b x^2+b^2 x^4}}{5 x^5 \left (a+b x^2\right )}-\frac{a^3 \sqrt{a^2+2 a b x^2+b^2 x^4}}{11 x^{11} \left (a+b x^2\right )} \]
[Out]
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Rubi [A] time = 0.125694, antiderivative size = 167, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 2, integrand size = 26, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.077 \[ -\frac{a^2 b \sqrt{a^2+2 a b x^2+b^2 x^4}}{3 x^9 \left (a+b x^2\right )}-\frac{3 a b^2 \sqrt{a^2+2 a b x^2+b^2 x^4}}{7 x^7 \left (a+b x^2\right )}-\frac{b^3 \sqrt{a^2+2 a b x^2+b^2 x^4}}{5 x^5 \left (a+b x^2\right )}-\frac{a^3 \sqrt{a^2+2 a b x^2+b^2 x^4}}{11 x^{11} \left (a+b x^2\right )} \]
Antiderivative was successfully verified.
[In] Int[(a^2 + 2*a*b*x^2 + b^2*x^4)^(3/2)/x^12,x]
[Out]
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Rubi in Sympy [A] time = 16.7292, size = 138, normalized size = 0.83 \[ \frac{16 a b^{2} \sqrt{a^{2} + 2 a b x^{2} + b^{2} x^{4}}}{1155 x^{7} \left (a + b x^{2}\right )} + \frac{2 a \left (a + b x^{2}\right ) \sqrt{a^{2} + 2 a b x^{2} + b^{2} x^{4}}}{33 x^{11}} - \frac{8 b^{2} \sqrt{a^{2} + 2 a b x^{2} + b^{2} x^{4}}}{165 x^{7}} - \frac{5 \left (a^{2} + 2 a b x^{2} + b^{2} x^{4}\right )^{\frac{3}{2}}}{33 x^{11}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate((b**2*x**4+2*a*b*x**2+a**2)**(3/2)/x**12,x)
[Out]
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Mathematica [A] time = 0.0287521, size = 61, normalized size = 0.37 \[ -\frac{\sqrt{\left (a+b x^2\right )^2} \left (105 a^3+385 a^2 b x^2+495 a b^2 x^4+231 b^3 x^6\right )}{1155 x^{11} \left (a+b x^2\right )} \]
Antiderivative was successfully verified.
[In] Integrate[(a^2 + 2*a*b*x^2 + b^2*x^4)^(3/2)/x^12,x]
[Out]
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Maple [A] time = 0.01, size = 58, normalized size = 0.4 \[ -{\frac{231\,{b}^{3}{x}^{6}+495\,a{x}^{4}{b}^{2}+385\,{a}^{2}b{x}^{2}+105\,{a}^{3}}{1155\,{x}^{11} \left ( b{x}^{2}+a \right ) ^{3}} \left ( \left ( b{x}^{2}+a \right ) ^{2} \right ) ^{{\frac{3}{2}}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int((b^2*x^4+2*a*b*x^2+a^2)^(3/2)/x^12,x)
[Out]
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Maxima [A] time = 0.692885, size = 50, normalized size = 0.3 \[ -\frac{231 \, b^{3} x^{6} + 495 \, a b^{2} x^{4} + 385 \, a^{2} b x^{2} + 105 \, a^{3}}{1155 \, x^{11}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b^2*x^4 + 2*a*b*x^2 + a^2)^(3/2)/x^12,x, algorithm="maxima")
[Out]
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Fricas [A] time = 0.260481, size = 50, normalized size = 0.3 \[ -\frac{231 \, b^{3} x^{6} + 495 \, a b^{2} x^{4} + 385 \, a^{2} b x^{2} + 105 \, a^{3}}{1155 \, x^{11}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b^2*x^4 + 2*a*b*x^2 + a^2)^(3/2)/x^12,x, algorithm="fricas")
[Out]
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Sympy [F] time = 0., size = 0, normalized size = 0. \[ \int \frac{\left (\left (a + b x^{2}\right )^{2}\right )^{\frac{3}{2}}}{x^{12}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b**2*x**4+2*a*b*x**2+a**2)**(3/2)/x**12,x)
[Out]
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GIAC/XCAS [A] time = 0.270948, size = 93, normalized size = 0.56 \[ -\frac{231 \, b^{3} x^{6}{\rm sign}\left (b x^{2} + a\right ) + 495 \, a b^{2} x^{4}{\rm sign}\left (b x^{2} + a\right ) + 385 \, a^{2} b x^{2}{\rm sign}\left (b x^{2} + a\right ) + 105 \, a^{3}{\rm sign}\left (b x^{2} + a\right )}{1155 \, x^{11}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b^2*x^4 + 2*a*b*x^2 + a^2)^(3/2)/x^12,x, algorithm="giac")
[Out]